Question 249731
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The given quadratic has no rational factors, hence you either have to complete the square or used the quadratic formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ x\ -\ 1\ =\ 0]


so *[tex \Large a\ =\ 1], *[tex \Large b\ =\ -1], and *[tex \Large c\ =\ -1].  Just plug in the numbers.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a} ]


And do the arithmetic.  By the way, the positive root of your quadratic is a particularly interesting number.  It is called the golden ratio and is the ratio of the long side to the shorter side of the golden rectangle.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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