Question 249751
I assume the equation is
{{{y = 2x^2 + 8x + 1}}}<br
When the equation of a parabola is in the form {{{y = ax^2 + bx +c}}}, then the x coordinate of the vertex is {{{(-b)/2a}}}. In your equation, the "a" is 2 and the "b" is 8, so the x coordinate of the vertex is
{{{(-(8))/2(2) = (-8)/4 = -2}}}<br>
Now that we know the x coordinate of the vertex we can use the equation to figure out its y coordinate:
{{{y = 2(-2)^2 + 8(-2) + 1}}}
{{{y = 2(4) + 8(-2) + 1}}}
{{{y = 8 + (-16) + 1}}}
{{{y = -7}}}<br>
So the coordinates of the vertex are: (2, -7)