<PRE><B>Question 249567</B>
Equations/249567 (2009-12-14 02:59:25): factor 125x3 + 64y3&lt;br&gt;

You can use the following formula to factor the sum of 2 cubes:&lt;br&gt;

(a^3+b^3)=(a+b)*(a^2–a*b+b^2)&lt;br&gt;

In this specific case, a=5x and b=4y&lt;br&gt;

Then we can easily substitute these into our formula&lt;br&gt;

{{{(5x+4y)(25x^2-5x*4y+16y^2)}}}&lt;br&gt;

{{{(5x+4y)(25x^2-20x*y+16y^2)}}} simplify and final answer&lt;br&gt;

As a note, the difference of two cubes can be found using the following formula:&lt;br&gt;

(a^3–b^3)=(a–b)*(a^2+ab+b^2)&lt;br&gt;

Answer 181746 by chosenpoint(20) on 2009-12-14 04:59:57&lt;br&gt;</PRE>