Question 249375
(15)
(5 ) 
THIS IS A COMBINATION PROBLEM.
15 ITEMS TAKEN 5 AT A TIME OR:
15!/[5!(15-5)!]
15*14*13*12*11*10*9*8*7*6*5*4*3*2*1/[(5*4*3*2*1)(10*9*8*7*6*5*4*3*2*1]
NOW CANCEL OUT TO GROUP (10*9*---*2*1)
15*14*13*12*11/5*4*3*2*1
360,360/120=3,003 GROUPS OF 5 PROBLEMS CAN BE CHOSEN.