Question 249326
(x+2)(x-2)=32
x^2+2x-2x-4=32
x^2-4-32=0
x^2-36=0
(x+6)(x-6)=0
x-6=0
x=6 the length of the original side of the square.
Proof:
(6+2)(6-2)=32
8*4=32
32=32