Question 249108
Is the "1." meant to signify this is your first problem?  Or is your problem actually 1.7x?  I'm going to presume my first thought to be correct.


Parallel, perpendicular, or neither?
7x-4y=4  and  x-4y=3


Facts:
1.  In order for two lines be parallel, they must share the same slope.
2.  In order for two lines be perpendicular, the product of their slopes must equal -1.
3.  The easiest form of identifying the slope is by expressing the equation in this form:  {{{y=mx+b}}} where m = slope.


{{{7x-4y=4}}}
{{{-4y=-7x+4}}}
{{{y=(-7x/-4)+(4/-4)}}}
{{{y=(7/4)x-1}}}  <--- slope is {{{7/4}}}


{{{x-4y=3}}}
{{{-4y=-x+3}}}
{{{y=(1/4)x-(3/4)}}}  <--- slope is {{{1/4}}}


Analize the results:
1.  {{{7/4}}} is not equal to {{{1/4}}}, therefore these lines are not parallel.
2.  {{{(7/4)(1/4)=7/16}}}, therefore these lines are not perpendicular either.
3.  The answer to this problem is: neither.


Just for kicks, here's how their graphs look like:
{{{y=(7/4)x-1}}} is represented in red
{{{y=(1/4)x-(3/4)}}} is represented in green
{{{graph (400, 400, -10, 10, -10, 10, (7x/4)-(1), (x/4)-(3/4))}}}