Question 31474
the midpoint of the hypotnuse of a right triangle is equidistant from the vertices.
WHAT IS THE TRIANGLE NAME?MNO?

given: angle MON is a right angle,
OK...ASSUMING MNO IS THE TRIANGLE
MN IS HYPOTENUSE. 
 P is the midpoint of MN
SO MP=PN.
NOW IF WE TAKE MN AS DIAMETER AND P ITS MIDPOINT AS CENTRE AND DRAW A CIRCLE
IT SHOULD PASS THROUGH O,SINCE ANGLE MON=90 AS GIVEN AND A SEMICIRCLE SUBTENDS 90 ANGLE AT ANY POINT ON ITS CIRCUMFERENCE AND VISE VERSA.AS O LIES ON CIRCLE AND PI NTHE CENTRE PO=RADIUS = DIAMETER/2=MN/2=MP=PN AS P  IS MIDPOINT OF MN. 

Prove: MP= PN =OP

MN IS 






Prove: MP= PN =OP