Question 249030
f(x) = 11(x-5)^2 +7
=11(x^2-10x+25)+7
=11x^2-110x+275+7
=11x^2-110x+282
a=11, b=-110, c=282
It has a minimum because a is positive.
axis of symmetry: x =-b/2a = 110/22 = 5
y=11(5-5)^2 +7 =7
coordinates of the vertex (5,7)
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Ed
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{{{graph(500,500,-2,8,-2,18,11(x-5)^2+7)}}}