Question 249008
When the length of a square is increased by 6 and the width is decreased by 4, the area remains unchanged. Find the dimensions of the square. 

Let x be the length of a side of the square.
Then x*x = x^2 is the area of the square.

From the givens we have:

(x+6)*(x-4) = x^2

Expanding we have:

x^2 + 2*x - 24 = x^2

Simplifying:

2*x = 24
x = 12