Question 248992
Are attitudes toward shopping changing? 
Sample surveys show that fewer people enjoy shopping than in the past. 
A recent survey asked a nationwide random sample of 2577 adults if they agreed or disagreed that "I like buying new clothes, but shopping is often frustrating and time-consuming." 
The population that the poll wants to draw conclusions about is all U.S. residents aged 18 and over. 
Suppose that in fact 62% of all adult U.S. residents would say "Agree" if asked the same questions. 
What is the probability that 1610 or more of the sample agree?
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population mean = sample mean = 0.62
sample std = sqrt[0.62*0.38/2577] = 0.0096
sample proportion = 1610/2577 = 0.6240
z(0.6240) = (0.6240-0.62)/0.0096 = 0.4167
P(x >= 1610) = P(z >= 0.4167) = 0.3385
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Cheers,
Stan H.
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