Question 248856
Determine where the two lines 
x+4y=3 and 
2x-6y=8 intersect?

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Multiply thru the 1st equation by 2:
2x + 8y = 6
2x - 6y = 8
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Subtract the 2nd Eq from the 1st and solve for "y":
14y = -2
y = -1/7
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Substitute in x + 4y = 3 and solve for "x":
x + 4(-1/7) = 3
x - 4/7 = 21/7
x = 25/7
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Cheers,
Stan H.