Question 248716
3x-2y=-14
3x+5y=-14 

Subtract the terms of the two equations:

(3-3)*x + (-2-5)*y = -14 - (-14)
0*x -7*y = 0
-7y = 0
y = 0

Substitute y=0 in the first equation:

3*x - 2*0 = -14
3*x = -14
x = -14/3