Question 248694
the product of a number M and six less than M is -5 . what is the sum of all possible values of M ?

M*(M-6) = -5
M^2 - 6M + 5 = 0
(M-5)*(M-1) = 0
So: M=5 or M=1 so the sum of the two solutions is 5+1 = 6