Question 248682
Find three consecutive integers such that the sum of the suares of the smaller two is equal to the square of the largest

Let x be the first integer,
Then the other two integers are x+1 and x+2.

Then we have:

x^2 + (x+1)^2 = (x+2)^2
x^2 + x^2 + 2x + 1 = x^2 + 4x + 4
x^2 - 2x - 3 = 0 

Solve for x and then calculate x+1 and x+2.