Question 248693
the equation for a line is y=mx+b
we have x,y, and m but not b
so we are solving for b

so we plug in your info
y=mx+b
1=1/2*(-6)+b
1=-3+b
add 3 to both sides
4=b
so now we write the equation 
y=(1/2)*m+4
or y=m/2+4
to graph the line we need at least to points
we have (-6,1)
we need another
we have two choices.
we know that when x=0 y=4 from the equation y=mx+4
b is called the y intercept
we also know that we can find another point on the line by using the slope

if we plot (-6,1) we know that for every y x increases two 
add one to y and 2 to x

so we can go (-4,2)
let's see if that works in our equation
y=mx+b
2=-4(/2)+4
2=-2+4
2=2
yes 
so we can use (-6,1), (-4,2)  and (0,4) or any two of them
end
since we only need two points to plot a line
just out of curiosity 
where would x be if y were 3
y=mx+b
3=1/2(x)+4
subtract 4 from both sides
-1=x/2
multiply by 2 (both sides)
-2=x
(-2,3)
which fits right in to our pattern
(-6,1), (-4,2), (-2,3),(0,4)