Question 248641
Let {{{h}}} = height
Let {{{x}}} = side of square base
The volume is
{{{V = x^2*h}}}
given:
{{{10 = x^2*h}}}
{{{h = 10/x^2}}}
The area of the closed box is:
{{{f(x) = x^2 + x^2 + 4*x*(10/x^2)}}}
{{{f(x) = 2x^2 + 40/x}}} m2  answer