Question 248545
(1/2)/1=1/2
(1/4)/(1/2)=1/2
r=1/2 Geometric sequence.
{{{a[n]=a[1]r^(n-1)}}}
(1/2)^(n-1)=1/1024
log[1/2]((1/2)^n-1)=log[1/2](1/1024) Finding n
n-1=10
n=11
{{{S[11]=a[1]((1-r^n)/(1-r))}}}  Sum of a finite geometric sequence.
={{{1((1-(1/2)^11)/(1-(1/2)))}}}
=.9995/.5
=1.999... the sum