Question 248212
Use the quadratic formula to solve the equation.
 If the equation has no real number solutions, so state.
x^2 + 7x + 2 = 0
:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
In this equation: a=1; b=7; c=2, so you have:
{{{x = (-7 +- sqrt( 7^2 - 4*1*2 ))/(2*1) }}}
:
{{{x = (-7 +- sqrt(49 - 8 ))/2 }}}
:
{{{x = (-7 +- sqrt(41))/2 }}}
Two solutions
{{{x = (-7 + 6.403)/2 }}}
x = {{{(-.597)/2}}}
x = -.2985
and
{{{x = (-7 - 6.403)/2 }}}
x = {{{(-13.403)/2}}}
x = -6.7015