Question 248484
Let x, x+2 & x+4 be the 3 numbers.
x^2+(x+2)^2=(x+4)^2+20
x^2+x^2+4x+4=x^2+8x+16+20
2x^2+4x+4-x^2-8x-36=0
x^2-4x-32=0
(x-8)(x+4)=0
x-8=0
x=8 ans. for the smallest number.
8+2=10 ans. for the middle number.
8+4=12 ans. for the laegest number.
Proof:
8^2+10^2=12^2+20
64+100=144+20
164=164