Question 31402
To see if this happens, lew x be the length and let y be the width:
2(x+y)=96
y=48-x (subsitution:)
AreA:
xy=24
Subsitute for y:
x(48-x)=24
48x-x^2=24
-x^2+48x-24=0
x^2-48x+24=0
Use the quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (48 +- sqrt( (-48)^2-4*1*24 ))/(2*1) }}} --> REMOVE NEGATIVE SIGN
{{{x = (48 + sqrt( 2304-96 ))/(2) }}} 
{{{x = (48 + sqrt( 2208 ))/(2) }}} 
x=47
y=1

47*1=47
So it is not possible.
Paul.