Question 248364
Let {{{x}}} = price of a bun in cents
Let {{{y}}} = price of a patty in cents
Let {{{b}}} = number of boys
Let {{{g}}} = number of girls
given:
{{{b*y + g*x = b*x + g*y + 1}}}
subtract {{{b*x}}} from both sides
{{{b*y - b*x + g*x = g*y + 1}}}
Subtract {{{g*x}}} from both sides
{{{b*y - b*x = g*y - g*x + 1}}}
{{{b*(y - x) = g*(y - x) + 1}}}
Divide both sides by {{{y - x}}}
{{{b = g + 1/(y - x)}}}
{{{b - g = 1/(y - x)}}} answer