<PRE><B>Question 248291</B>
x^3 - 6x2 +13x - 10=0
do the rational roots test by dividing +- a/d = +- 10/1
The possible rational factors are +- 10, 5, 2, 1
testing these we find that 2 is a zero.
next we divide x^3 - 6x2 +13x - 10 by x-2 and get x^2-4x+5 which is a quadratic.
x^2-4x+5=0
x^2-4x   =-5
x^2-4x+4=-5+4 completing the square.
(x-2)^2=-1
x-2=+-sqrt(-1)
x=2+i, x=2-i  the other 2 zeros.
.
Ed</PRE>