Question 248255
The hang-time function V(T) = 48T2, relates vertical leap to hang time. A player has a vertical leap of 29 in. What is his hang time?
V(t)={{{(48T^2)}}}
29={{{(48T^2)}}}
{{{(29/48)}}}={{{(T^2)}}}
.604={{{(T^2)}}}
{{{sqrt(.604)}}}={{{(sqrt(T^2))}}}
.777sec=T