<PRE><B>Question 248091</B>
Find the vertices of the hyperbola 
4x^2-16y^2=64 
Divide thru by 64 to get:
x^2/16 - y^2/4 = 1
a = 4 ; b = 2
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Vertices: (-4,0); (4,0)
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Cheers,
Stan H.</PRE>