<PRE><B>Question 247755</B>
Find the area of a regular hexagon with the given measurement 4 inches 

for that answer I got 25 square root of 3
For any regular polygon with n sides of length s:
Area = (ns^2/4)*cot(180/n)
= 6*16*cot(30)/4
= 24*sqrt(3)
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the area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. find the length of a side of the regular hexagon/
I got 2 and the square root of 4 
Area of the triangle = (3*144/4)*cot(60)
Area = 108*cot(60)
Area = 36*sqrt(3)
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36*sqrt(3) = (6s^2/4)*cot(30) = (3s^2/2)*sqrt(3)
3s^2 = 72
x = 2sqrt(6)
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