Question 247798
To find the x-intercept, set f(x)=0 and solve for x.
{{{-x^2+1=0}}}
{{{-x^2=-1}}}
{{{x^2=1}}}
{{{x=1}}} and {{{x=-1}}}
When x=0, f(x)=1
When x=1=-1, f(x)=0
When x=2=-2, f(x)=-3
When x=3=-3, f(x)=-8
{{{ graph( 300, 300, -5, 5, -10, 10, -x^2+1) }}}