Question 247823
Write an equation of the line containing the specified point and parallel to the indicated line (3,-4), 5x-6y=4
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First, find the slope, m, of the line.  To do that, put it into slope-intercept form y = mx + b.  That means solve for y.
5x-6y=4
y = (5/6)x + something, doesn't matter.
The slope is 5/6
All lines parallel to it have the same slope.
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Use y = mx + b and the point to find b:
-4 = (5/6)*3 + b
b = -13/2
--> y = (5/6)x - 13/2 is parallel and thru the point.