Question 247828
<font face="Garamond" size="+2">

The formula is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a} ]


But in order to know what *[tex \Large a], *[tex \Large b], and *[tex \Large c] are, you have to put your equation into standard form.  Standard form is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ax^2\ +\ bx\ +\ c\ =\ 0]


Your equation is


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ =\ 30]


Add -30 to both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ -\ 30\ =\ 0]


So far, so good, but you don't have a first degree term.  That means *[tex \Large b] must be zero!


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ +\ 0x\ -\ 30\ =\ 0]


Now you can see that *[tex \Large a\ =\ 2], *[tex \Large b\ =\ 0], and *[tex \Large c\ =\ 0]


Just plug the numbers into the formula and do the arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>