Question 247827
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x^2\ -\ 23x\ -\ 6\ =\ 0]


*[tex \Large a\ =\ 4], *[tex \Large b\ =\ -23], and *[tex \Large c\ =\ -6]


And the formula is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a} ]


Just plug in the numbers and do the arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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