Question 247772
log (base 81) 9= i have 81^x=9 but i do not know what to do next. 
81 is 9^2, so 9 = 81^(1/2) or sqrt(81)
{{{log(81,9) = 1/2}}}
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log (base x) (1/36)=-2 i have x^-2=(1/36) but i dont know what to do next
{{{x^-2 = 1/36}}}
{{{1/x^2 = 1/36}}}
{{{x^2 = 36}}}
x = 6