Question 247730
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Given: Equations {{{y = 3x(EQN1)}}} and {{{y = -3x (EQN2)}}}


In {{{EQN1}}},{{{y=3x}}}
let Fy=0: {{{0=3x}}} --> {{{x=0}}}
y=1: {{{1=3x}}} ---> {{{x=1/3}}}
y=2: {{{2=3x}}} ---> {{{x=2/3}}}
y=3: {{{3=3x}}} ---> {{{x=3/3=1}}}
y=-1: {{{-1=3x}}} ---> {{{x=-1/3}}}
y=-2: {{{-2=3x}}} ---> {{{x=-2/3}}}
y=-3: {{{-3=3x}}} ---> {{{x=(-3/3)=-1}}}

We see the points in the graph:

{{{drawing(300,300,-5,5,-5,5,grid(1),graph(300,300,-5,5,-5,5,3x), blue(circle(0,0,.10)), blue(circle(1/3,1,.10)),blue(circle(2/3,2,.10)),blue(circle(1,3,.10)),blue(circle(-1/3,-1,.10)),blue(circle(-2/3,-2,.10)),blue(circle(-1,-3,.10)))}}}


In {{{EQN2}}}, {{{y=-3x}}}
Let Fy=0: {{{0=-3x}}} ---> {{{x=0}}}
y=1: {{{1=-3x}}} ---> {{{x=-1/3}}}
y=2: {{{2=-3x}}} ---> {{{x=-2/3}}}
y=3: {{{3=-3x}}} ---> {{{x=-3/3=-1}}}
y=(-1): {{{-1=-3x}}} ---> {{{x=1/3}}}
y=(-2): {{{-2=-3x}}} ---> {{{x=2/3}}}
y=(-3): {{{-3=-3x}}} ---> {{{x=(-3/-3)=1}}}

We see the points:
{{{drawing(300,300,-5,5,-5,5,grid(1),graph(300,300,-5,5,-5,5,-3x),circle(0,0,.10),circle(-1/3,1,.10),circle(-2/3,2,.10),circle(-1,3,.10),circle(1/3,-1,.10),circle(2/3,-2,.10),circle(1,-3,.10))}}}


Thank you,
Jojo</font>