Question 247618
suppose (~) is an angle in standard position whose terminal side lies in quadrant II.
if sin (~) = 12/13, find values of sec (~)
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sin is y/r
y = 12 and r = 13
x = sqrt[13^2-12^2) = sqrt(169-144) = sqrt(25) = 5
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But x is negative in Quadrant II so x = -5
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sec(~) = r/x = 13/-5 = -13/5
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Cheers,
Stan H.