Question 247371
I haven't done this in a while so here goes.
formula for the center of a circle
(x-h)^2+(y-3)^2=r^2
(0,3) is the center (h,k)
so far we have 
(x-0)^2+(y-3)^2=r^2 
r= the distance from the center to the circle
the point 3,7 is on the circle
a^2+b^2=r^2
(7-3)^2+(3-0)^2=r^2
16+9=25
(x-0)^2+(y-3)^2=25
now to put it in standard form


x^2+(y-3)^2=25