Question 247379
4x^2 - 23x - 6 = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
x=(23+-sqrt[-23^2-4*4*-6])/2*4
x=(23+-sqrt[529+96])/8
x=(23+-sqrt625)/8
x=(23+-25)/8
x=(23+25)/8
x=48/8
x=6 ans.
x=(23-25)/8
x=-2/8
x=-1/4 ans.