Question 247403
A department store manager claims that at least 45% of persons who visited this store make a purchase. In a sample of 400 persons who visited the store 150 made a purchase. Test the manager’s claim at the 3% significance level. 
a.State the null and alternate hypothesis.
Ho: p >= 0.45 (Claim)
H1: p < 0.45 
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sample proportion = 150/400 = 0.375
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test statistic: z(0.375) = (0.375-0.45)/sqrt[0.45*0.55/400] = -3.0151...
critical value for left-tail test with alpha = 3%: z = -1.8808
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Since the test stat value is in the reject interval, reject Ho.
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b. Determine the rejection region for the decision rule.
critical value for left-tail test with alpha = 3%: z = -1.8808
The reject interval is all z-values less than -1.8808
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c. which equation listed below would you use?
The equations are not listed.
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d. Using the statistical calculator or manual calculation what is the observed statistic and what is your decision regarding the null hypothesis. Provide a one sentence answer.
Answered above.
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Cheers,
Stan H.