Question 247368
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First take out a 6


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 12y^2\ +\ 54y\ -\ 30\ =\ 6\left(2y^2\ +\ 9y\ -\ 5\right)]


Then notice that *[tex \LARGE 2\,\cdot\,1\ =\ 2]


And *[tex \LARGE \left(2\,\cdot\,5\right)\ +\ \left(-1\,\cdot\,1)\ =\ 10\ -\ 1\ =\ 9]


And *[tex \LARGE -1\,\cdot\,5\ =\ -5]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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