Question 247341
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The area of a rectangle is given by


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ lw]


So the length, in terms of the area and the width must be:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ l\ =\ \frac{A}{w}]


The perimeter of a rectangle which is the distance around the rectangle and therefore the amount of fence required to enclose it is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ 2l\ +\ 2w]


Substituting for *[tex \Large l] gives us a function for perimeter in terms of width for any given area


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ \frac{2A}{w}\ +\ 2w]


For your 350 square foot area:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ \frac{700}{w}\ +\ 2w]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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