Question 247337
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Numbers that are divisible by 5 have a last digit of either 0 or 5.  Numbers that are divisible by 2 are even numbers.  Since any number that ends in 5 is not an even number, the number we are looking for must end in 0.  Numbers that are divisible by 3 have a sum of digits that is divisible by 3.  Since 7 is not divisible by 3, any number that qualifies by the fact that the sum of the digits is 7 also qualifies on non-divisibility by 3.  Since this is a 3-digit number less than 300, the hundreds digit must be either 1 or 2.  7 minus 1 is 6, so one possibility is 160.  7 minus 2 is 5 so the other possibility is 250.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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