Question 247321
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The sum of the interior angles of an *[tex \LARGE n]-sided polygon is given by the formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (n\ -\ 2)\cdot\,180]


So set the formula equal to your given sum and then solve for *[tex \LARGE n]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (n\ -\ 2)\cdot\,180\ =\ 180]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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