Question 247281
let n=first integers
and n+2 the second
n+(2(n+2))=12+n+2

n+2n+4=14+n
3n+4=14+n
subtract 4 from both sides
3n=n+10
subtract n from both sides
2n=10
n=5
 n+2=7
check
5+2(7)=12+7
19=19
ok