Question 247271
{{{log(2)x + log(2)(x+4) = 5}}}
{{{log(2)(x*(x+4)) = 5}}}
{{{x*(x+4) = 2^5}}}
{{{x^2 + 4x = 32}}}
{{{x^2 +4x - 32 = 0}}}
{{{(x+8)(x-4) = 0}}}
x = -8 or x=4
Can't do logs of negatives, so only x=4 works
Check your answer
{{{log(2)4 + log(2)(8) = 5}}}
{{{2 + 3 = 5}}} check!