Question 247189
{{{(x^2+7x-18)/(x^2+4x-45)}}}


First, we need to factor the numerator and denominator:
{{{((x+9)(x-2))/(x+9)(x-5))}}}


Now, we can cancel equal numerators and denominators, so we get:
{{{(x-2)/(x-5)}}}


Done!