Question 31327
Rule: logA - logB= log (A/B)
Your problem rewritten is:
log[(3+x)/(3-x)]= log 3
Take the anti-log to get:
(3+x)/(3-x)=3
3+x=3(3-x)
3+x=9-3x
4x=6
x=(3/2)
Cheers,
Stan H.