<PRE><B>Question 31327</B>
One of the rules of logarithms is,
logA - logB = log(A/B)
Applying this rule to your eqn,
log{(3+x)/(3-x)} = log(3)
Since you have the log of something on one side of the equation equals the log of something else on the other side then we can say that the something on the one side equals the something else on the other side, giving,
(3+x)/(3-x) = 3
multiply both sides by (x-3), to give
3 + x = 3(3-x) = 9 - 3x
4x = 6
x = 1.5
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