Question 246960
x^2+4x=5
x^2+4x-5=0 You forgot to transfer the 5.
You also need to use {( }) for this equation so you won't get lost.
This is what i got:

x=(-4+-radical[4^2-4*1*-5])/2*1
x=(-4+-radical[16+20])/2
x=(-4+-radical36)/2
x=(-4+-6)/2
x=(-4+6)/2
x=2/2=1 ans.
x=(-4-6)/2
x=-10/2
x=-5 ans.