Question 246912
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ 388]


which is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 388\ -\ y]


But


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 3y]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3y\ =\ 388\ -\ y]


Solve for *[tex \LARGE y] then multiply by 3 to get *[tex \LARGE x]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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