Question 246886
 need to find the length of a rectangle which is 4 more than the width. if the area of the triangle is 96 sq inches, i have to find the dimensions of the triangle.

Let x be the width of the rectangle.

Then the length is x + 4.

Since the area of the rectangle (length times width) is 96 we have:

x*(x+4) = 96 or
x^2+4x-96 = 0

Solve this quadratic equation for x (the width). Then calculate the length as x+4.