Question 246819
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Let *[tex \Large x] represent the measure of angle B.


Then *[tex \Large 2x\ + 30] represents the measure of angle A and *[tex \Large 3x] represents the measure of angle C.


Since the sum of the measures of the interior angles of a triangle is 180 when the angles are measured in degrees, and since I presume that you meant "measure of angle A is 30 <b><i>degrees</i></b> more than twice the measure of angle B" in your problem statement, we can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ +\ B\ +\ C\ =\ 2x\ +\ 30\ +\ x\ +\ 3x\ =\ 180]


Solve for *[tex \Large x] to get the measure of B and the others follow from that.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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