Question 246747
Alice is twice as old as Judy, who is younger than Alex by 3 years. 
Let Alex = x
Let Judy = x-3
Let Alice = 2(x-3)
If the sum of their ages is 27, our equation becomes:
{{{x+(x-3)+(2(x-3))=27}}}
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Now solve for x to determine Alex's age.
Then deduct 3 to determine Judy's age.
Then multiply Judy's age by 2 to determine Alice's age.
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Remember to check your answers to ensure their ages add up to 27.
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I'll let you take it from here.  :)