Question 246759
A wheel is marked off into 8 sections numbered 1 to 8.
The numbers 1, 4, and 7 are colored red; the numbers 2 and 8 
are colored blue; and the numbers 3, 5, and 6 are colored yellow.
You spin the wheel TWICE. . . 
What is the probability of the first outcome being a number
BETWEEN 5 and 8 exclusive and the second outcome being blue?
a. 4/64
b. 2/8
c. 4/8
d. 4/16
<pre><font size = 4 color = "indigo"><b>
The sample space has 8 elements,

{1R, 2B, 3Y, 4R, 5Y, 6Y, 7R, 8B}

The probability that the first spin is between 5 and 8 exclusive is
the probability that it is 6Y or 7R.  that's 2 out of 8 or {{{2/8}}}. 

The probability that the second spin is blue is the probability that 
it is 2B or 8B.  that's also 2 out of 8 or {{{2/8}}}.

These are independent events, so the probability that both will occur
is the product, {{{(2/8)*(2/8)=4/64}}}.

(I have no idea why whoever wrote this problem doesn't reduce fractions
but since they didn't, neither did I).

Edwin</pre>